Hello everyone,
Please I need your help...
When performing the accuracy of an Assay / Blend method, using a Buffer pH 4.0: MeOH (70:30) as a solvent solution, we recovered 102%.
As the amount of methanol decreases, we obtain the following:
Buffer: MeoH 70:30 = 102.0%
Buffer: MeoH 80:20 = 101.6%
Buffer: MeoH 90:10 = 101.0%
Buffer = 101.0%
Please, Could someone help me understand this phenomenon?
Thanks in advance!