http://www.periodni.com/preparation_of_solutions.php?scq=H2SO4&mm=98.0768
This a very easy tool..just put in the details, chemical formula and other details you will get the weight or volume of compound to be prepared..
I think it would be useful for you to see how to make this simple calculation and to learn the elementary lab procedures to subsequently prepare the solution.
You need to know 3 things in order to do the calculation:
(1) What concentration of the solution to make: 150 mM = 0.15 M
(2) What volume you want to make: Let's suppose you want to make 100 mL = 0.1 L
(3) The formula weight of the solute (written on the label): 84 g/mole
The calculation goes like this:
0.1 L x (0.15 mole/L) x 84 g/mole) = 1.26 grams.
Notice how the unit labels L and mole cancel out because they each appear once in the numerator and once in the denominator, leaving only grams.
Dissolve 1.26 grams of NaHCO3 in a little less than 0.1 L of double-distilled water in a 100-ml graduated cylinder or volumetric flask, using Parafilm to cover the top of the cylinder or flask so that you can invert it without spilling (some types have stoppers that you can use instead of Parafilm). Since the solubility of NaHCO3 in water at room temperature is about 1 M, it will dissolve easily. Add enough water to bring the volume to the 100 ml line. Remix the solution.
A late answer.
Please also consider the purity of your NaHCO3 powder.
i.e.: If its purity is 98%, and you need 1.26 grams/100 mL,
1.26 x 100/98 = 1.29 grams.
The amount you should add to water is slightly more than the previous number.
This answer may not be useful for you anymore, I just add it for others seeking similar answers.
Best,
koray
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