While evaluating the cytotoxicity of a sample in cell line, what percentage of cell viability is considered inorder to conclude that the sample is toxic. Like if 80% of cell survives, is the sample toxic or not
Hello Chandana Malakar
You need to calculate the IC50 value of the sample candidate by performing
dose-response curve of the sample treatment on the cells by MTT assay. It indicates the toxicity of the sample. It is a quantitative measure that shows how much a particular inhibitory substance is needed to inhibit a biological component like the cells by 50%. The IC50 value is correlated with drug potency that is the amount of drug candidate necessary to produce the effect. The lower the IC50 value the more potent is the drug candidate.
I hope this will help.
Best.
Hi Chandana Malakar , this is a very broad topic. But let me generalized it to you for the simplicity. In general when evaluating the toxicity of a substance in cell based assays, we calculate the LC50 value (which is call the the concentration of your substance required to kill 50% of the cellular population).
But is is important to under stand that this LC50 value is a very relative parameter. It is entirely depending on what is your effective working concentration.
Let say for example you have two drugs, A and B. Let assume both of them have LC50 values at 1 mM.
Let say drug for drug A, the effective working concentration for cell work is 1 uM. And Let's say for the drug B, the effective working concentration is 25 uM.
Now even-though both drugs have the same LC50 value, you can obviously see the drug B is more toxic than drug A.
There are many different toxicity assays you can perform (i.e., MTT, Titer Glow, Titer Blue, etc..)
If you ever question a single toxicity assay method, you can always perform two different assays just to assure your results.
Hope this information helps.
Calculation of LC50 value by MTT assay seems to be the best way.we can take two concentrations below it and two above in it for some selected time of exposure
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