We know that OCV of graphite anode vs Li/Li+ is approximately 0.4 V, So how it is possible to get the potential level of 4 V vs Li/Li+ in the graphite anode in overdischarge tests ?

Please take a look at the attached figure in which an overdischarge test has been applied on LiCoO2/graphite battery cell. What is interesting for me, is the potential of the cathode which is not changing during overdiscarge.

1st Question) As we know during the discharge process, electrons enter the cathode through the external circuit which the cathode potential need to be decreased not being constant. So, why in this curve, cathode potential is not changing ?

2nd Question) How the potential of 4 V vs Li/Li+ is accessible on anode material (i.e. graphite anode) by taking this into consideration that OCV of graphite vs Li/Li+ is about 0.4 V and if the operating potential get over that, graphite experinces anodic reaction and will be corroded and destroyed at such high potentials of 4 V.

Please propose your technical notes in terms of electrochemical aspects

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