DEar Vaniska

i'm sorry but there is something that i cannot understand in your question.

IS it your protein pure? Because if it is pure 1mg is = 1000ug if it is not pure than your bradford quantify the total proteins and to estimate how much is your protein, you need to assess the level of purity (e.g running an SDS page and performing densiometric analisys or by SEC or by HPLC reverse phase).

Ciao

Manuele

Did you mean that you lysed a tissue sample that had a wet tissue weight of 1 mg? If so, you just need to multiply the amount of volume you have in ml by 7. For example, with 50 ul lysis volume, 7 ug/ml x0.05 ml = 0.35 ug in 50 ul.

Or if you just want to know how much of your protein solution you need to use to get 1 mg of protein, 1000 ug/7 ug = 142.86. You would need 142.86 ml of your protein sample to have 1 mg of protein.

First, you should know how many mg you weighted: for example, you took a 100 mg (0.1 g) of the sample.

Second, you should know how many uL you have of the proteins that you extracted it. For example, 200 uL of the proteins.

Third, follow the calculation:

7 ug/mL * (200/1000) mL = 1.4 ug in 100 mg of the sample

weight in ug = (1.4 ug * 1 g ) / 0.1 = 14 ug in 1 g of the sample.

Generally speaking 1000 uL (1 mL) weighs 1000 mg (1 g). If your question is how to translate your value of 7 ug/mL, then it would be 7 ug/g of dry weight.

Thank you so much foryour answers.