Dear researchers I would like to learn how to quantify extract component A. I run extract at concentration of (0.2815 mg/ml). The extract was spiked with isotope labelled deuterated (A-d3) standard compound at 50 µg/ml OR (0.05 mg/ml). Every response will be highly appreciated. Please look at following data
Extract concentration = 0.2815 mg/ml
Peak area of extract component A = 500 (molecular weight: 314)
Peak area of isotope standard (A-d3) = 1500 (molecular weight: 317)
Spiking concentration of isotope standard (A-d3) = 50 µg/ml (0.05 mg/ml)
Concentration of component A (%) = ?
Hi,
I will use X to designate Concentration of A in sample (mg/ml).
Then
X=(500*314*0.05mg/ml)/(1500*317) = 0.0165 mg/ml in injected sample
Concentration of component A in extract (%) = X*100/0.2815 = 5.86%
Hope this helps!
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