Dear researchers,
May I know how to make 10N of NaCl solution?
I used the equation below :
To prepare 10mL of 10N of NaCl,
Weight(g)= Normality (N) x Equaivalent weight of substances x volume of water added (L)
= 10 x 40 (molecular weight of NaCl) x 0.01
= 4g
So, 4g of NaCl is needed to dissolve in 10mL of water to give 10N NaCl.
Am I right?
Thank you.
Dear Jennifer Leong
Normality is a measure of concentration equal to the gram equivalent weight per liter of solution.
Valence of Sodium chloride (NaCl)= 1
Molecular weight (Mw) of NaCl= 58.443
For making NaCl Solution 10(N), add water to 584.43(g) NaCl till its volume reach to 1(lit).
Dear Jennifer Leong, thé calculation of Dr. Mina Karimi-Avargani is correct, but you want only 10 ml:
584.43g ........for..........1L=1000ml
Thus: dividing by 100
5.8443g ........for.......... 10ml
So, you have to solubilize 5.8443g until to reach a tatal volume of 10ml of both: solute NaCl and solvent H2O. My Regards
Jennifer Leong May I point out to all that the solubility of NaCl in water is 360 g/1000 g pure water at T = 25 °C. It is not possible to dissolve 584 g of NaCl in 1 L of water or 5.84g in 10 mL... Not sure why one of the answers has got 11 recommendations...
Dear all, the question is about the theorical calculation only. However, its practical feasability should consider the threshold of maximun saturation concentration as stated by Prof. Alan F Rawle. Additional information are presented in the following similar RG thread. My Regards
https://www.researchgate.net/post/What-is-the-maximum-concentration-of-sodium-chloride-in-water
As Alan F Rawle pointed out, you need to raise the temperature to make such dissolution a possibility- but even that won't do. NaCl has 384 g/l solubility at 100 C. Try remoltely close CaCl2 or KI insttead if you want. And, if you can synthesize NaCl nanoparticles, (say Na hydroxide/alkoxide and alkyl hallide or HCl gas, in an organic water-absorbent media), then might be some stability of nanoparticles would be possible.
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