I need help with HMF determination in honey samples using the method by White. I had to decrease the weight of honey used (limited amounts available) so instead of 5g I am using 0.5g and multiplying by the dilution factor. Do I need to correct the equation for quantification (the contant value)? And if so, how? Thank you for any help you can give me.
5-(hydroxy-methyl)-2-furaldehyde (HMF) is widely recognized as a marker of quality deterioration, caused by excessive heating or inadequate storage conditions, not only in honey, but in a wide range of foods containing carbohydrates. HMF is naturally present as a consequence of the action of normal honey acidity on reducing sugars usually at room temperature, but its quantity increases upon thermal treatment and/or storage at improper temperatures. About your question, i think, no problems, you can use 0.5g instead 5g and in the equation you will be like that (you will put 0.5g instead of W). W is the weight of honey sample. So i think you will not change anything, just put your real weight in your equation. You may need these pdf in your experiments. Good luck.
HMF(mg/kg) = (A284 − A336) × 149.7 × 5/W
HMF(mg/kg) = (A284 − A336) × 149.7 × 5/0.5
Thank you very much for your answer Amr... it was defenitely helpful, our results are making more sense.
Best regards to you and your research
why we discard the first 10ml of the filtrate during determination of HMF in honey
by spectrophotometric method?
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