Well, the peaks in Raman spectrum appear at the wavelengths detuned from your excitation wavelength by energy of vibrational quantum (phonon for solid). It might be that there are multiple qunata excitation, so you will see a series of lines. I am not sure about selection rules for solid state phonons, but it seams that you will have only two quanta transitions allowed with such polar compounds. re-heck it in a textbook.
Your material is very far from being crystalline, there is no network left, the disorder is total. Then in that case, due to a generalized Brillouin zone folding effect, Raman scattering only accesses the phonons state density. So your Stokes and anti-Stokes spectra should be continua extending from roughly 50 to more than 1000 cm^1. That gives you the full set of phonon energies in your glass.