So if my yeast strain has a KanMX marker and also has Leu2 post transformation, can I screen both Auxotrophic and dominant markers at the same time on the same plate ex Sc- Leu with G418?
If it is possible then why, if not possible then why not?
It is an interesting question. I do not know the correct answer (haven't tested it though) but generally we use one type of selection plate (either auxotrophic or antibiotic) for transformant selection. For auxotrophic selection, synthetic minimal dropout media is used. In contrast, for antibiotic selection, rich media with antibiotic is used. If the strain contains both KanMX marker and LEU2 gene, theoretically it should grow on SC Leu- with G418 (bearing in mind that the expression of KanMX marker gene could be downregulated in synthetic minimal medium).
Yes, you can test both dominant and recessive markers in Saccharomyces cerevisiae on the same plate, but there are important considerations to keep in mind to ensure the experiment works properly:
✅ Requirements for testing dominant and recessive markers simultaneously:
1. Choosing the appropriate medium:
Recessive markers (e.g., ura3Δ, leu2Δ): Require selective dropout media (e.g., -URA or -LEU) to identify cells lacking a specific gene function.
Dominant markers (e.g., KanMX): Require a selective agent such as an antibiotic (e.g., G418) that only cells with the resistance gene can survive.
🔸 Solution: Use a combined selective medium, such as:
-URA + G418, to test both a ura3Δ background (for plasmids with URA3) and a KanMX resistance marker.
2. Spotting samples on the plate:
Make sure to spot different strains (with different genotypes) in clearly separated locations (e.g., drops or grids) to distinguish the results accurately.
3. Controls:
Include known positive and negative control strains for each marker, so you can correctly interpret growth or lack thereof.