Hi All, 

Based on this paper by Lakens 2013 (http://journal.frontiersin.org/article/10.3389/fpsyg.2013.00863/full) I understand there are two recommended ways for calculating Cohens d for within subjects measures. 

1. Cohen's drm (which assumes the correlation between measures is known) and can be calculated as:

Cohen's drm=( Mdiff/sqrt(SD12+SD22-2*r*SD1*SD2))*sqrt(2(1-r))

Where Mdiff is the difference in means, SD1 and SD2 are the standard deviations of these means and r is the correlation between measures.

the variance of Cohen's drm can be calculated using the following:

Vdrm=(1/n+drm2/2n)2(1-r)

where n is the sample size. Again this assumes the correlation is known. 

2. Cohens dav (which ignores any correlation between measures and used the average of the standard deviations).

Cohen's dav=Mdiff/((SD1+SD2)/2)

My question is how to calculate the variance of Cohens dav (Vdav)? 

Can it be calculate in a similar manner to the calculation for  independent groups - simply by substituting d for dav?

Vdav=(n1+n2/n1*n2)+(dav2/2*(n1+n2))

if so some elements of this equation appear unclear as the sample size is the same for both observations.

Thanks in advance, 

Becca

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