I want to do methylation specific PCR. So, I am doing bisulfite treatment. In some protocols 3M stock of sodium bisulfite is used which finally becomes 2.6 M in solution (Herman et al). some uses sodium metabisulphite in final conc. of 2.31 M. I am using 1.5 M stock  of sodium metabisulphite . As 1 mole of sodium metabisulphite is equal to 2 moles of sodium bisulphite . thus this will be equivalent to 3 moles of sodium bisulphite and the final conc. of sodium metabisulphite is 1.3M with this stock. so, according to me it should be equivalent 2.6 M of sodium bisulfite as is there in Herman's protocol? Am I right or I should treat sodium metabisulphite as sod. bisulphite  and use the same conc. as mentioned for sod. bisulphite.  Does everybody uses this sod. metabis. for bisulfite treatment  and use at same conc. as is mentioned in the protocols for sodium bisulfite sodium bisulfite is also used? I am really confused with this sodium metabolism. and sod. bisulphite. So, please help me to overcome this confusion. 

More Lalita Sharma's questions See All
Similar questions and discussions