It is noted that for OER process, the Gibbs reaction free energy is defined by
𝛥𝐺 = 𝛥𝐸 + 𝛥𝑍𝑃𝐸 − 𝑇𝛥𝑆 + 𝛥𝐺U + 𝛥𝐺PH
where the last term is the pH value correction.
𝛥𝐺PH=pH×kBTln10.
How this term affect the Free energy diagram for four-electron transfer of ORR process?
The deltaG1, deltaG2,.. in pH = 0 are different from those deltaG1, deltaG2,.. in pH = 14?
In the alkaline condition (pH = 14), the calculated overpotential is different from that in adic condition (pH=0)?
Yurii V Geletii
Both OER and ORR proceed through a sequence of 1-electron oxidation steps, each one is pH dependent. You need to build a Pourbaix diagram to see which pathway is dominant at a given pH
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