Impulse voltage= 1 volt with and 500ns domain
Will the structure change by injecting a small surge voltage into a solar panel? Will the values of the series and shunt resistance change?
A forward voltage impulse of one volt amplitude and duration of 500 ns will not damage the solar cell. In forward direction the solar cell is equivalent to a parallel Cf -rf in series with the Rs the series resistance of the solar cell.
rf is the forward junction resistance and and Cf is the forward capacitance of the solar cell and it is composed of two capacitances the junction capacitance and the diffusion capacitance. At the beginning of the voltage pulse applications, the voltage will appear at Rs while the voltage on the capacitance will be zero. With elapsing of time the diode capacitance will be charged and the junction voltage increases. This will continue to the end of the time of the pulse where a part of the voltage will be dropped on the junction and the rest will be dropped on the series resistance. Since the time constant is large because the solar cell is large then the pulse ends with with only a fraction of the voltage is dropped on the junction and the current is still smaller that the maximum forward current that can burn the solar ell.
The series and shunt resistances will remain the same except some heating of the series resistance which may then increase.
In summary the behavior of the solar cell is similar to the behavior of the power diode.
For more information please follow the link:Presentation comprehensive study of the pin diodes
Best wishes
A forward voltage impulse of one volt amplitude and duration of 500 ns will not damage the solar cell. In forward direction the solar cell is equivalent to a parallel Cf -rf in series with the Rs the series resistance of the solar cell.
rf is the forward junction resistance and and Cf is the forward capacitance of the solar cell and it is composed of two capacitances the junction capacitance and the diffusion capacitance. At the beginning of the voltage pulse applications, the voltage will appear at Rs while the voltage on the capacitance will be zero. With elapsing of time the diode capacitance will be charged and the junction voltage increases. This will continue to the end of the time of the pulse where a part of the voltage will be dropped on the junction and the rest will be dropped on the series resistance. Since the time constant is large because the solar cell is large then the pulse ends with with only a fraction of the voltage is dropped on the junction and the current is still smaller that the maximum forward current that can burn the solar ell.
The series and shunt resistances will remain the same except some heating of the series resistance which may then increase.
In summary the behavior of the solar cell is similar to the behavior of the power diode.
For more information please follow the link:Presentation comprehensive study of the pin diodes
Best wishes
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