In preparation of iron catalyst supported on MgO,by impregnation, what shud b the mass of iron nitrate nonahydrate taken for iron loading of 1% ?
First of all you have to determine hwo much catalyst are preparing?
Then you calculate the amount of Iron needed for the 1%. Using this amount and the molar mass of Fex(NO3)y you back calculate the mass needed of the nitrate.
i.e;
1.0 mole of Fex(NO3)y has (x multiplied by 55.8 gm Fe)
? mole of Fex(NO3)y are required to have the mass corresponds to the 1% above.
Dear Sir,
I would like to ask that if i want to prepare 10 grams of catalyst (Fe supported on MgO ), say 1 percent loading, would it mean, 0.1 grams of iron (mass of Fe(NO3)3 calculated corresponding to 0.1 grams) , and 9.9 grams of MgO. and then any amount of water can be added?
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