I am working on HUVEC cells in order to Establish the Oxidative Stress Injury Model Induced by H2O2. I want to treat the cells with 5mM H2O2 from 30%h2o2 stock solution for 16 hours. How to prepare 5 mM hydrogen peroxide from 30% H2O2 stock solution?
Hello,
How will I calculate?
First of all I need to know the molarity of my H2O2 solution. For this I will need the density of H2O2 which is 1.11kg/L or 1111 g/L. this means that m = 1111* 0.3 (30%) = 333.3 g in 1 liter of solution.
n = m/M.
M of H2O2= 34.01g/mol
so n = 333.3/34.01 = 9.80 mol/L. So your solution is 9.80 M.
Then, to prepare a 5 mM (0.005 M) solution you dilute the solution which is 9.80 M using the rule CiVi = CfVf
Sofiane Benyamina hello Thank you for your attention.
so, If I want to make a 5mL hydrogen peroxide solution, according to your statement, should I dilute 2.5 microliter of 30% hydrogen peroxide with 4997.5 microliter of water?
Exactly, 2,55 microliter of 30% hydrogen peroxide with 4997.45 microliter of water.
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