I have FeCl2 crystals and I want to produce FeSO4.7H2O based on the reaction below: FeCl2 + H2SO4 = FeSO4 + HCl
I dissolved the FeCl2 crystal in water, added equivalent amount of H2SO4 to react with all Fe (No excess) and increased the temperature to 40 C and 90 C (separate experiments). But the yield at 40 C is 70% and at 90 C is less than 30%. Any idea how I can improve the yield?