I am using a scavangers study. I am facing difficulty for this calculation. Please help me. I have a solution of 100ml TBA. As I understand from youtube, I calculated that I need to take like this, Is it right?
M = 0.005 moles / 0.2 liters = 0.025 M
The molecular weight of t-BuOH is 74 g/mol.
Mass = 0.005 moles * 74 g/mol = 0.37 g
Density of t-BuOH is approximately 0.78 g/ml.
Volume (ml) = mass (g) / density (g/ml)...
Volume = 0.37 g / 0.78 g/ml ≈ 0.47 ml
Therefore, you would need approximately 0.47 ml of tertiary butyl alcohol to make a 5 millimole solution in 200 ml.
You first need to know the concentration of your stock solution(s) in moles per liter.
The mass in grams of your substance divided by its molecular weight will give you the moles of your substance (the solute).
The moles of your solute divided by the volume of solvent it is dissolved in will give you its concentration (in moles per liter) of your stock solution i.e., its molar strength (molarity).
Now you need to find the volume of this solution that contains 5 x10-3 moles of that substance.
Volume (in liters) x Molarity = moles of the substance
volume x the molarity of your stock solution = 5 x 10-3
Therefore the volume (containing 5 millimoles) in liters = 5 x10-3/ the molarity of your stock solution.
Philip G Penketh Can you please give me a calculation ? It is very hard for me to understand. Thank you for yor reply
Please, did you eventually get a solution to this problem? If yes, please can you explain to me how you calculated it. Thank you very much.
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