Oxidation of of palmitic acid yields 7 NADH + 7 FADH2 + 8 acetyl-CoA in 7 cycles of mitochondrial beta oxidation. Every acetyl-CoA yields 3 NADH + 1 FADH2 + 1 GTP (=ATP) during Krebs cycle. Considering an average production of 3 ATP/NADH and 2 ATP/FADH2 using the respiratory chain, you have 131 ATP molecules. However you have to used 2 ATP molecules for the initial activation of every fatty acid that is going to be oxidized in the mitochondria.
I hope it helps!
Oxidation of of palmitic acid yields 7 NADH + 7 FADH2 + 8 acetyl-CoA in 7 cycles of mitochondrial beta oxidation. Every acetyl-CoA yields 3 NADH + 1 FADH2 + 1 GTP (=ATP) during Krebs cycle. Considering an average production of 3 ATP/NADH and 2 ATP/FADH2 using the respiratory chain, you have 131 ATP molecules. However you have to used 2 ATP molecules for the initial activation of every fatty acid that is going to be oxidized in the mitochondria.
I hope it helps!
It may be little different if we put the currently accepted value of 2.5 ATP for NADH2 and 1.5 for FADH2 instead of 3 ND 2 respectively.
Ya its little bit typical to answer !!!!
But, Here is description:
Theoretically ATP yield for every oxidation cycle can be maximum upto 17, as NADH produces 3 ATP, FADH2 = 2 and end product, acetyl COA governed Citric Acid Cycle produces 12 ATP. Cumulatively in practice it comes 14 ATP for a one time full oxidation cycle and it only possible when we assume, 2.5 ATP per NADH molecule and 1.5 for each FADH2 molecule and 10 fro citric acid cycle, which seems to be irrational. But for better understanding we put this kind of assumption. However palmitate is 16 carbon containing saturated fatty acid.
So, for an even-numbered saturated fat (C2n) ("C" indicating the number of carbon atoms and noted 2n is in the subscript), n - 1 oxidations are required, and the final process yields an 1 more acetyl CoA i.e. for palmitate if 2n=16 then n=8, which required n-1 oxiation i.e 7, so there will be 7 FAD, 7 NADH and 8 acetyl COA which will produce 1.5 ATP, 2.5 ATP and 10 ATP respectively and cumulatively it will be calculated 108 where 2 ATP were used in the initial activation of fatty acid so 2 ATP will be subtracted and total number of ATP will become 106. But if you go with the thereotical yields and have larger production ATP source then values of NADH, FAD and ATP produced by the full rotation of citric acid cycle will produce 3, 2, 12 ATPs. Together ATP number will become 131 and 2 will be subtracted as required for initial activation of fatty acid so you will remain with 129 !!!!!!!!!
The answer will vary, depending on if you are using 2.5/1.5 ATPS per NADH/QH2 or a different value.
Negi has it but sometimes we argue that one ATP goes into activation and the next equivalent goes into shifting the equilibrium to the products.
Oxidation of of palmitic acid yields 7 NADH + 7 FADH2 + 8 acetyl-CoA in 7 cycles of mitochondrial beta oxidation. Every acetyl-CoA yields 3 NADH + 1 FADH2 + 1 GTP (=ATP) during Krebs cycle. Considering an average production of 2.5 ATP/NADH and 1.5 ATP/FADH2 using the respiratory chain, you have 108 ATP molecules. However, 2 ATP molecules were consumed during the initial activation of Palmitate to Palmitoyl-CoA which is going to be oxidized in the mitochondria. So, net energy output = (108 - 2) = 106 ATP.
Answer 129 ATP is according to old concept and in modern practice, this theoretical yield is not attained. So, practically net ATP gain is 106 ATP.
Thanks!
Palmitic Acid has 16 carbons
16/2=8
8 acetyl coA * 10 ATP/acetyl CoA = 80 ATP
(8-1=7) 7 cycles * 4 ATP/cycle= 28 ATP
-2 eq ATP for FA activation
80 + 28 - 2 = 106 net ATP yield
=(N/2 *5 ATP) + (N/2 * 12 ATP) - ATP
N =Number Carbon = 16
=(16/2 * 5)+(16/2 *12)-2 = 40 +96 -2 = 134 ATP..
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