Here is a general guide on converting concentrations:
When measuring ozone in Milligrams per Hour ( mg/hr ), the concentration cannot be determined unless the flow rate itself is known.
1 ug/ml = 1 mg/l = 1 g/m3 = 1 gamma
1 ml is = to 1 cc.
So, to determine the actual concentration if given mg/hr., one first must convert from mg/hr to mg/l. This is done by using the flow rate. If an ozone generator pumps out 250 mg/hr at a flow rate of 1 liter per minute, then:
The ozone generator produces 4.1667 mg/min ( 250 mg/hr divided by 60 ). Since we now know that we have 4.1667 milligrams of ozone each minute, and the flow rate is 1 liter each minute, we now have 4.1667 mg for each liter, or 4.1667 mg/l.
By looking at our chart, we now know that we have an ozone generator that produces 4.1667 ug/ml.
To determine the concentration, we can use the formula given by Saul Pressman:
0.5 % X 1.4 gm/l = 7 ug/ml
Only, let's convert it properly, first, by using the mathematical version with the correct units of measurement:
1m3 is about 1.293kg of air. you sould not go above 30ppb of ozone, but if you would like to preform desinfection of air and room, you souhld go to 2.5ppm of ozone, what is equal to 3.25 mg of ozone per m3.
6 gram is enough for 1856m3 od air.
maybe i made sone error in caculation?! please double check
Could you help me? I can't use this method if I have a volume for the room what I messure. So I have a 17,25m^3 room and an ozon generator, that fills the room up to 10ppm in 4 mins and has a 117 CFM ventillator. How much g/hr does this generator produce? Can someone share the calculation with me?
I understand the calculation suggested, but the decay rate of ozone has not been considered. If the generator produces 6 gr of ozone/hour, after 1hour i do not have 6 gr of ozone, because it has a mean life and decay. Even though 6 gr has been produced. I am interested in how the ozone decay in time in air or in water.