Hemoglobin is formed by the tertiary structure of 2 alpha chains and 2 beta chains. The alpha is normal in sickle cell anemia, but the beta chains have a mutation and form Hb-S.

But, in a sickle cell trait, there is a possibility of both Hb-S and Hb-A. This is because the cell can have 2 beta polypeptides. Lets call the normal one 'b' and the mutated one 'b*'. (referring to the polypeptides not the alleles)

So i'm assuming Hb-A is aabb while Hb-S is aab*b*. What stops the cell from making aab*b - i.e., a hybrid between the normal beta polypeptide and the mutated one in the same hemoglobin?

Hemoglobin electrophoresis works primarily on charge (rather than mol wt as SDS PAGE does). Since, the polypeptides are not separated, and whole Hb is loaded, in sickle cell trait, shouldn't we be expecting three bands? 

The sickle cell mutation, glutamate is replaced by valine so there's a charge difference. So if in a Hb, there is a difference of one/two mutant polypeptides, the charge will also differ. So,

  • HbA = aa-bb = 1 glutamate in each b chain.
  • HbS = aa-b*b* = both glutamate replaced by valine
  • Hb? = aa-b*b = only one glutamate replaced. glutamate still present on wild polypeptide
  • (the aa-bb notation here depicting phenotype of polypeptides not genes)

    So if there are three electrophoretic possibilities (theoretically?), why only two bands? And since the 3rd possibility is midway of the two, I suppose, it can't be ignored as minor.

    Does hemoglobin in sickle cell trait, have hybrids of normal and diseased beta polypeptide? -

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