11 November 2017 5 774 Report

Hello. I found that specific capacitance of three and two electrode in supercapcitor are different even with the same electrode.

The specific capacitance of three electrode (Cs,3) is four times lager than that of two electrdoe (Cs,2), that is Cs,3 = 4 * Cs,2.

So, to compare specific capacitance (Cs,2) in two electrode with specific capacitane performed in three electrode system (Cs,3, other reference data), Do I have to multiply Cs,2 by 4?

Thanks.

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