The MB+-modified aptamer, MB+-(IV), reveals a quasi-reversible redox wave at E° =−0.35 V vs the Ag quasi- reference electrode. Accordingly, the MB+-(IV) conjugate was reduced to MBH-(IV), while applying, on a Hg-roughened Au electrode, a constant potential of−0.6 V vs the Ag wire reference electrode. The MBH-(IV) conjugate was oxidized to the original MB+-(IV) conjugate by applying a potential corresponding to−0.2 V vs the Ag wire.
I can understand that they did CV to find E’, but how the constant potential has been applied?