Hi, I'm trying to make my own borate buffer as per the specification in the picture attached. Concentration of 0.4 N, and a pH value of 10.2.

I found a lot of different recipe online and I came up with my own calculation, hope someone can help me to verify it.

Boric acid, H3BO3 has a MW of 61.83.

First, the equivalent mass of H3BO3 has to be determined, since H3BO3 has 3 hydrogen ions, thus,

Equivalent mass = 61.83/3 = 20.61 -- (1)

Grams of chemical required = Normality desired x Equivalent Mass x Volume Required (L)

= 0.4 N x 20.61 x 1 L

= 8.244 g

Therefore, i need to weight 8.244 grams of boric acid, and dissolved it in 1 litre of deionized water. Then I will use NaOH to increase the pH to 10.2.

As for the NaOH, how many molar should I make to increase the pH of the buffer? Can I just drop some NaOH tablet into the buffer directly, and only add in drop of NaOH solution when the pH is near? As I found adding drop by drop of NaOH is taking too long.

Thanks to anyone who helps.

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