Sometimes alpha helices have segments of 3/10 helix at the end. In the transition area, there are residues for which the amide N is equally close to the carbonyl oxygens of the residues 3 and 4 before, and carbonyl O are equally close to amide N's 3 or 4 residues ahead. The carbonyl O has two lone pairs and presumably could bind to both if the geometry is right, but could the amide N, with one H, bond to two carbonyl groups? If so this could allow a smooth transition from alpha helix to 3/10 as a helix is stretched- with the alpha helical bonds getting longer and weaker while the 3/10 bonds are forming and taking over, until eventually there are strong ideal 3/10 bonds and the alpha bonds are stretched out of existence.