check the links below  and hope to be useful to you

http://www.slideshare.net/yomology/raman-spectroscopy

http://pubs.acs.org/doi/abs/10.1021/j100285a047

Mohamed:

Thank you very much for the links. Looks like there is another factor to consider -the role of H-bond. I will follow up to see what progress can I make on this issue.

Umesh

Dear Umesh,

Bonds involving deuterium and tritium are somewhat stronger than the corresponding bonds in hydrogen. The C-D bond is about 10 times stronger than the C-H bond, which means the C-D bond is more resistant than the C-H bond. This is why D2Owould have higher melting point (3.82 °C), boiling point (101.72 °C), density (1.017 g/cm3), temperature of maximum density (11.6 °C), heat of vaporization (10,864 cal/mol) and viscosity than H2O.

The wavelengths of all deuterium spectroscopic lines are shorter than the corresponding lines of light hydrogen. Thus, the wavenumber of all deuterium spectroscopic lines would be bigger than the corresponding lines of light hydrogen.

The fact that there is a net shift to higher wavenumber in deuterated ethanol, tells you there is a net compression in the resultant vibrational modes which could not have been due to possible combined bending of C-O-H (EtOH) modes and the stretching of C-O modes. Deuterated ethanol is behaving just like a single cellulose microfibril in compression in a Raman light spot within a 2D network of cellulose microfibrils being increasingly put in tension.

Thus, the questions to ask here would be: 'what modes must the C-O modes and the C-O-D modes be in to result in a net compression vibrational mode?'

Ref:

http://cdn.intechopen.com/pdfs-wm/35655.pdf

Akwasi

Thanks Akwasi for the reply. I plan on reading the PDF.

Umesh