In Buck Converter DCM mode, Inductor current = Vo / R.
Why is the capacitor current not considered for the inductor current?
C=dq/dv, variation of charge with variation of voltage, or is voltage sensitive component , hence charging current is neglected…
That my imply that the capacitor is fully charged when the inductor could be with zero current if there wasn't any resistor in parallel to the capacitor.
This is due to the assumption that, in steady-state, the capacitor voltage is constant. The capacitor current is given by Cdvc/dt, so with a constant Vc its current is zero and the resistor and inductor currents are equal.
In real life, some capacitor voltage ripple is present. If the buck converter has been correctly designed the ripple is low enough so its effect can be neglected.
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