Dears
I am working on single-effect absorption chiller. In the refrigerant leg where pure water (as refrigerant) exits the evaporator, its exergy decreases because its temperature is under ambient temperature. Is this right? Why does this happen?
Dear sir
It is,based on physical exergy
T/T0-ln(T/T0)-rT0ln (p/p0)
Thank you for your answer dear Mr. Mehdi Aliehyaei
Since fluid change to steam so motion of molecule increases so entropy increases and exergy decreases.
S=klnw
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