If you have peaks it means your sample is crystalline.
I think you need to read about XRD and understand what it can do. Then formulate a question about your sample that can be answered by XRD. When you understand your question and you understand XRD then you will have your answer.
If you have peaks it means your sample is crystalline.
I think you need to read about XRD and understand what it can do. Then formulate a question about your sample that can be answered by XRD. When you understand your question and you understand XRD then you will have your answer.
Your sample is clearly a crystalline material. I depends on what you want to do. If you only want to identify the phase, your data is enough and peaks positions that match with known phases. With the help of Scherrer formula, you can calculate average grain size.
Quantification of crystallinity requires Rietveld refinement analysis, which in turn first requires mineral phase identification. I recommend reading the attached article.
Article Rietveld Refinement strategy for quantitative phase analysis...
Thank you respected Ian J Slipper, Zamin Mamiyev , Fazan Gul, Rafael for your valuable suggestions however most of the papers showed the presence of peak @ 18-20 degree for crystallinity..
As you have the diffraction patterns between 40° -70°, the first information is that you have a a sample with a crystalline structure. The second information that you can get is the interlayer distance between diffraction planes. You can use the Bragg relation (2 d Sin theta = n lambda, where d is the interlayer distance, theta is the diffraction angle and lambda is the wavelength of X-ray source that you use). For each diffraction pattern you have to calculate d. If you have a software, you can determine the crystal structure of your sample.
It looks like you have two different populations of crystallite size here. One is poorly crystalline – broad peaks between 10-40 and one which is more crystalline – sharp peaks between 40-80.
What is the material?
As has been mentioned above you could use the Scherrer equation to find an approximation of the two different sizes.
The counts are quite low relative to the background which is quite high, maybe some fluorescence here.