Hi Muhammad, I suggest you to explain first your sample before to identify your ketone functional group using your FTIR Spectrum.
However, if this spectrum is an assigment and want to know what compound is? I can only give a clue from Dr Hardinger's five zone analysis :
Zone 1 extends from about 3700 to 3200 cm-1 and is used to locate the following bonds: the alcohol O-H, the terminal alkyne C-H, and the amine or amideN-H. The alcohol peak is usually broad and wide and can be distinguished easily. The more concentrated the solution is with O-H molecules, the more likely it is to form hydrogen bonds. Since it is easier to stretch hydrogen bonds (because the oxygen pulls away the electrons), less energy is required and the peaks appear broader. Alkyne C-H bonds have strong peaks around 3300 cm-1.
In Zone 2, absorptions by alkane C-H bonds, aryl and vinyl C-H bonds, aldehyde C-H bonds, and carboxylic acid C-H bonds can be found. The sp3 C-H bond peaks can usually be found slightly to the right of the 3000
cm-1 mark. The sp2 C-H bonds can be distinguished because they are located slightly to the right of the 3000 cm-1 mark. Both of these C-H bonds have many tiny peaks.
Evidence of the presence of an aldehyde can be found around 2700 cm-1 and 2900 cm-1
mark. Lastly, the carboxylic acid O-H bond appears as a wide, broad peak in the
spectrum.
In Zone 3 reaches from 2300 to 2100 cm-1. Here, we can find the absorptions of alkyne triple bonds and nitrile triple bonds. Their peaks are variable in intensity.
In Zone 4 we find absorption peaks by carbonyl double bonds. These peaks are usually very strong and intense. They allow us to identify the existence of ester, aldehyde, ketone, carboxylic acid, or amide functional groups. Here is an important note: if conjugation exists among the carbonyl group, the peak can shift 20 to 40 cm-1 lower because the bond has more single bond character. Aromatic overtones, tiny peaks caused by aromatic rings, may also appear. The last zone (Zone 5) has absorption peaks caused by alkene double bonds and aromatic carbon –carbon bonds. Benzene has two peaks: one at around 1600 cm-1 and one around 1500 cm-1.
It will be very difficult to just see a carbonyl stretch and conclude is a ketone what about esters, aldehyde, amide. You need another technique NMR, UV and elemental analysis especially for synthetic work. As for natural product analysis you need 2D NMR.
The spectrum is consistent with a short or branched chain aliphatic ketone, e.g. Acetone, 3methyl2butanone, 44dimethyl2pentanone. However there is not a good match to published ref spectra as the relative band strengths vary. Looking at the spectrum the band shapes and baseline look unusual, suggesting a poor spectrum to background balance distorting the bands