A voltammogram recorded for a solution containing a short peptide (30-40 amino acids) which has the oxidizable tyrosine (1), histidine (3) and methionine (1) , among others residues without redox properties, present only one oxidation peak. The oxidation potential is 200 mV lower than free tyrosine. Incubating this peptide with SDS, two oxidation peaks, occurring at the same oxidation potentials as free tyrosine and histidine residues, were obtained.
In other worlds: after SDS incubation, the oxidation peak of peptide shifts to more positive values (corresponding to tyrosine oxidation) and a new peak, of histidine, appeared.
The concentration used for these experiments not allow the detection of methionine; however, methionine oxidation occurs at high potentials.
The question is: how can be possible that the oxidation potential of a tyrosine residue of a folded peptide (I suppose that the peptide adopt a defined secondary structure) be lower than unfolded or even than free tyrosine?