The electrochemical oxidation of methionine on glassy carbon or boron doped electrodes at physiological pH occurs at a potential higher than + 1V while tyrosine or tryptophan, for example, is oxidized at 0.65 V. Considering this differences in oxidation potentials, why is methionine in vivo readily oxidized?

Nevertheless, the reduction of methionine sulfoxide into methionine by methionine sulfoxide reductases is the only reversible system (regarding the amino acids oxidation) and it has been postulated that this serves as a catalytic antioxidant mechanism against deleterious effects of oxidative stress on proteins.

Another example is the Amyloid beta –Cu2+ complex. There are many evidences that Cu2+ is binds to histidine residues at position 6, 13 and 14 and is reduced by methionine 35 residue. The reduction potential of Cu2+ is around -0.1 V whereas the oxidation potential of methionine is higher than +1 V. Since the difference is more than -1V why does this occurs?

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