I'm stuck at trying to make a 10mM stock solution of a drug (MW 145781.6g/mol) in 10ml of 0.01% DMSO. The concentration of the drug as stated on the pot is 2mg/ml.
Your drug with an MW of 145781.6g/mol (pretty big drug!) in the pot at 2mg/ml is at a concentration of 13.7 uM.
To achieve your wanted stock of 10mM you would have to concentrate the solution in the pot by a factor of about 725.
Well there is an easy calculation for mM
mM= (wt in gms / Mol.wt)/ Volume (Lit) X 1000
This formula should solve your problem
Good Luck
Molarity = moles/vol in L ... first u have to calculate moles and 1 mole is equal to its mol. wt. for ur case 10mM means .01M= moles/.01L , so moles=.0001 and wt in gram = no of moles * mol wt i.e, .0001X 145781.6 .. so make this sol in .01% DMSO solution...
hope this helps
good luck
Your drug with an MW of 145781.6g/mol (pretty big drug!) in the pot at 2mg/ml is at a concentration of 13.7 uM.
To achieve your wanted stock of 10mM you would have to concentrate the solution in the pot by a factor of about 725.
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