I carried out a laurdan titration to test different solvent polarity. I was testing new filters in the lab. I added laurdan to water, and carried out a titration. The same was done with ethanol and isopropanol. I worked out the generalised polarisation. For water I obtained +0.099; for ethanol I obtained -0.742 and for isopropanol I obtained -0.617. My question is: how does laurdan behaves in the solvents to obtain these results? Am I getting these results, because laurdan forms micelles in water, and inverted micelles in ethanol and isopropanol? So the tail is exposed to the solvent? but how do I explain the GP values?
You can read about the mechanism of the solvatochromic effect in
Article Laurdan solvatochromism: Influence of solvent polarity and h...
Based on this work, the authors did not use water for comparison with other solvents. This is related to your problem, how you write with the formation of micelles. Laurdan is more hydrophobic than hydrophilic. Therefore, it possibly forms reverse micelles. Look in the literature for CMC in water or do it yourself by examining the spectra depending on the concentration. Upon solubilization in micelles, emergent properties may appear in laurdan due to the quantum thermal phase transition in the case of the formation of straight micelles by laurdan. Determine GР in the order of ethanol, isopropanol, water always up to this Laurdan concentration. The quantum thermal phase transition can be found in
Preprint Quantum and thermal liquid -liquid phase transitions in aque...
Yuri Mirgorod thank you very much for help, I really appreciate it. I will look at the thermal phase transition.
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