I have read that CFU/g is converted to log CFU normally, especially for generate graph.
as Changing the numbers to the logarithm makes it easier to see small numbers and large numbers on the same graph.
For my case, I have calculated the CFU/g for fungi using selective agar, so I do not get much fungi in which plate (10-50 per colonies in each plate).
for example, the highest CFU/g i get is 5000 cfu/g only (the value is not very big), so is it necessary to convert it to log value? especially for analyzing the data using ANOVA? [of coz, the data have to be converted to log value, if the levene test for homogeneity of variance, P < 0.05]
log(CFU+1)= log(5000+1) = 3.69 log CFU/g
Dear Kuan Kin Pong,
I understand that you do not have the homogeneity of variance with numbers between 0 to 5000 cfu. However, the log transformation give you the homogeneity of variance and numbers between undefined to 3,69.
What is the log (0)? It is not defined. This is why you need to use log(0+1) = log (1) = 0
If you have no zero value, you do not need to use this transformation.
You can read : A review of issues related to measuring colonization of plant roots by bacteria by J.W. Kloepper · C.J. Beauchamp
Yours sincerely,
Dear , Kuan Kin Pong .
As I know it is not necessary to convert the CFU value to log value .
with my best greeting
Dear Pong
Hi
The convert CFU to Log is important to facilitate statistical analysis operations and not effect on your results.
Dear Kuan Kin Pong,
I understand that you do not have the homogeneity of variance with numbers between 0 to 5000 cfu. However, the log transformation give you the homogeneity of variance and numbers between undefined to 3,69.
What is the log (0)? It is not defined. This is why you need to use log(0+1) = log (1) = 0
If you have no zero value, you do not need to use this transformation.
You can read : A review of issues related to measuring colonization of plant roots by bacteria by J.W. Kloepper · C.J. Beauchamp
Yours sincerely,
Hi , Kuan Kin Pong,
I agree with Chantal J Beauchamp .
If you have no zero value, you do not need to convert to log value.
Best regards
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