I am comparing the antioxidant activities of five different species at different doses. According to the Tukey test, P > 0.05. How would you interpret this result?What does the lack of a significant difference indicate?
you should first run the ANOVA test to see whether there is any difference between treatments. If your p-value is > 0.05 then you have no evidence to reject the null hypothesis of mean differences between treatments, so the analysis is finished. On the other hand, if you reject the null hypothesis (p
If the p_value of ANOVA and tukey is greater than 0.05 so, there is no statistically significant difference in the antioxidant activities among the five species across the different doses. i.e. the antioxidant activities among the different species and doses are statistically similar.
You may need to ensure that your sample size is adequate to detect differences, also realize the assumptions of ANOVA.