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I have prepared a solution by mixing 200 ul of 1 mg/ml of compound A with 200 ul of 1 mg/ml of compound B and 200 ul of 1 mg/ml of compound c, then what will be the final concentration of compound A in mixture solution?
Thanks in advance
Sahil Kapur
Thanks a lot Sir Marcos Steola
I suppose it is calculated as follows:
C1* V1 = C2 * V 2
1 mg/ml * 200 ul = C2 * 600 ul
C2 = 0.3333 mg/ml
where C1 = Concentration of compound A ( 1 mg/ml)
V1 = Volume of solvent in which compound A was dissolved ( 200 ul)
C2 = Final concentration of compound A
V2 = Final volume of solution ( 200 ul + 200 ul + 200 ul = 600 ul)
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Marcos Steola
You are correct Sahil Kapur
Another way is consider like a simple dilution for 0,2 mL in final volume 0,6 mL.
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