TiCl4 is highly volatile, reacts with water and fumes in air (M pt= -24. 3; B pt= 136.5 C) It should be handled in an inert atmosphere in a fume cup board while wearing the protective gloves , clothes, eye gears along with some respiratory protection. Its container should be tightly closed and kept dry in a refrigerator. When used, immediately take it out of the refrigerator and open the container in a box having an atmosphere on N2 (g).Its known volume (by a 5.0 ml burette kept in this box) is immediately poured in a beaker containing ICE while keeping the temperature is less than 4C.Now take this cold beaker out of the box and make up the required volume(500.0 ml) by adding ice cold water. The beaker is kept at room temperature for some time so that following reaction is completed:

TiCl4 + 2 H2O --> TiO2 + 4 H Cl.

Determine its pH with the help of pH meter.

Suppose the pH of this solution is 3.It means that the conc. of H (+) is 10^-3 which is obtained from one mole of TiCl4. But this conc. has come from the diluted TiCl4. So conc. Of H (+) in the undiluted (original) TiCl4 is 500/5. 10^-3 or its pH=10^-1= - (-1) log 10=1

Dear Dr.Manohar Sehgal,

Thank you very much for spending your time with my question and giving full information about pH measurement