I am doing TPC assay. I obtained the equation y=0.0006x -0.0123 .
I started with 8g of dry plant powder for extraction and dissolved it in 80 ml of methanol.
I evaporated the total 80 ml volume by rotary evaporator and obtained 1 g of crude methanolic extract - i.e. from 8g of dry plant, I obtained 1g of crude methanolic extract.
Now , from this 1g of crude methanolic extract ,I took 2 mg and dissolved it in 1 ml of methanol(Concentration-2mg/ml). I used 1 ml in the FC assay.
Absorbance obtained- 0.055
from equation, x= 112.16 ug/ml
So for TPC = C x V/ M
Now ,here what will be V , 80 ml used initially or 1 ml used in the assay
and what will be M , 8g or 2mg?
and how can I convert mg GAE/g of dry extract to mgGAE/g of dry plant?
Kindly explain
- Badges
- Science topic
- Similar topics
- Geoscience
- Atmospheric Sciences
- Atmosphere
- Air
More Risha Hazarika's questions See All
Similar questions and discussions