I am currently working on phytoremediation. i want to know about calculations of making solution from lead acetate tri hydrate. the required amount of Pb in soil is 250mg/kg.
The molecular weight of your molecule is Pb (207) + Acetate 2x (118) + water 3x (54) = 379. Thus the part of lead in this molecule is 207/379 = 0.546. So, to get a solution of 250 mg/l water you have to add 250 x 1/0.546 = 458 mg of the leadacetate trihydrate to 1 l of water.
Thankyou so much for your answers C.A. (Kees) Kan Lydia Hernandez Rivera can you please tell me about how to make required solution which i mentioned before from the stock solution of lead acetate trihydrate