200 g fresh fruit puree is extracted with 200 ml of solvent on orbital shaker then filtration and desolvinization in rotary evaporator to obtain dry extract of 19 gram. Next 0.5 g extract was dissolved in 10 ml to obtain the concentration of 0.05g/ml. Next o.5 ml of the above diluted extract was used in FCR assay. Abs = 0.088

Caliberation equation is 0.0038x+0.0172(Range 20-200 mg/L)

calculation:

(0.088-00172)/0.0038 = 18.63 mg GAE/L.

Now for one gram it would be 0.186 mg GAE/g

Now what will be the unit express with 0.186 mg, either it is per gram extract, per gram sample or per gram dry weight of extract.

What will be the result on dry matter basis. If dry matter content of fruit is 17.5%

Please rectify if wrong.

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