Hello Pravin Wadekar,

Specific capacitance (F/g) of  electrode can be evaluated from charge-discharge curve with the help of the following equivalence:

C=(idt)/(m(Vf-Vi))

‘i’ the discharge current (A), ‘dt’ the discharge time (s), (Vf-Vi) is working potential window, and ‘m’ signifies mass (g) of active electrode. Here only discharge time is used as you have concerned.

plz go through my publications. It can help you. I'm attaching a few here.

links

Article Large scale flexible solid state symmetric supercapacitor th...

Article V2O5 encapsulated MWCNTs in 2D surface architecture: Complet...

Article V2O5 encapsulated MWCNTs in 2D surface architecture: Complet...

Dear Bidhan,

I gone through your research article but i have confusion in calculations. Kindly, check attached file. i want to keep current value but i am not getting properly.

First of all check the active electrode mass loading. It is very small (0.02 mg). Is it the mass loading per cm2 or what.

By the way as per ur considerations, i = 0.00002 A, dt = 100 s (approx.), (Vf-Vi)= 1 V, and ‘m’ = 0.0002 g. So, the capacitance = 100 F/g.

Thank you!

Yes mass is ~ 0.02 mg. Because I use glassy carbon electrode for analysis. Therefore mass loading is limited. Any alternative for it? to load maximum mass for electrochemical analysis.

hello pravin,

what is the area in which 0.02 mg has been deposited? Is it 1 cm2? or what? If that its very low and inconvenient. Though I believe that you will certainly deposit some electrode material such as metal oxide, sulfides or others on it. As carbon based electrode materials are known for conductivity and stability not for high performance supercapacitors (due to exhibiting EDLC not pseudocapacitance).

you can check the discussion for clearer view.

https://www.researchgate.net/post/What_should_be_the_active_mass_loading_preferable_for_supercapacitor_electrode_Is_it_low_or_high_mass_loading?

Thanks