I want to orally administrate 3mg/Kg of drug (MW=359.34) to mice that have an average body weight of 40g. The drug will be dissolved in DMSO and then put in their water bottle that contains 250ml of water (final concentration of DMSO is 1%).
Can anyone help me calculating the needed amount of drug solution that I have to prepare in order to have a final concentration of 3mg/kg?
I haven't done oral administration of drugs before and I am a little bit confused so any help would be highly appreciated.
Thanks a lot in advance
Hi Asma,
You may use the web tool to calculate
https://www.alfa-chemistry.com/solution-dilution-calculator.htm
Would like to help you but... what do you mean by "final concentration of 3mg/kg"?
mg/kg is usually a dose, not a concentration. A concentration would be mg/L.
The needed amount (mL) of drug solution depends on the concentration of the drug solution (mg drug per liter of DMSO-solution) and the intended daily dose.
You need to determine:
1. How much water does one mouse drink per day?
2. What is the intended total daily dose?
3. What is the maximum chemically possible concentration of the drug in DMSO?
4. What does the drug solution taste like? Will the mice drink it?
5. How can you make sure that each mouse receives exactly the intended daily dose (no less and no more) if they share a drinking bottle?
Things to consider:
The higher the drug concentration in the DMSO solution, the lower the volume that the mice need to drink (= the more you can be sure that they indeed drink the intended daily dose). On the other hand, if the drug has a taste that the mice may not like, a lower concentation increases the chances that they will drink it. Also, how would you ensure that none of the mice drinks too much?
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