I would like to carbamylate LDL, and need to use 0.1M NaBorate pH 8.0
I would appreciate feedback
First, use sodium tetraborate *10 H2O which is quite soluble in water. The anhydrous sodium borate dissolves too slowly. (76.3 g/L = 0.2M) . Also make a solution of Boric acid (H3BO3). (0.2M solution = 12.4 g/L). Starting with the sodium borate solution, place a pH electrode in it while stirring and slowly add the boric acid solution until the pH is 8.0 (Starts at ~ 9-9.5). You now have a 0.2M solution of sodium borate, pH 8.0. Add 1 volume of water to bring the concentration to 0.1 M.
Hi there,
you can also start from boric acid (6,18g for 1L final volume), dissolve it in 900mL of water, adjust pH with concentrated NaOH and then top up to 1L.
Please find the link for more understanding!
http://www.crscientific.com/experiment4.html
Borate Buffer
· 1. 4.76 g Boric Acid (Cat # B-1934)
· 2. 2.54 g Borax (Cat # B-0127)
· 3. 1000 mL of ddH2O
· 4. pH to 8.4 with NaOH
· 5. Sterile Filter
Dear Nick Chacos,
I followed your given protocol to prepare Borate buffer of pH 8.0, 0.1M.
As you have mentioned firstly i prepared 0.2 M sod. borate sol. 100ml, when i was adjusting its pH to 8.0 100ml of 0.2 M boric acid was used. Now, its final volume became 200ml.
Please tell me, now what will be the buffer concentration because my final vol. became 200ml of that buffer?
I am getting confused is it now 0.1M or 0.2M?
please resolve this.
Hi Lovely,
I have also read Nick's protocol and I'm currently using it in preparing 0.2M borate buffer, pH 8.0 as well. From what I understood, the final concentration of the 200ml is 0.2M borate buffer, and you have to add additional volume of water to dilute the buffer to 0.1M.
Hi John,
As we increase the volume, molarity will also get change. Molarity is inversely proportional to volume prepared. Right?
There should be some change in molarity.
Maybe these links will help you:
"Many procedures do not give a method of preparation for the borate buffer intended; it is important to express the ionic strength in terms of boron molarity." -from 2nd page of website
https://www.sigmaaldrich.com/content/dam/sigma-aldrich/docs/Sigma-Aldrich/Product_Information_Sheet/b0394pis.pdf
https://www.reddit.com/r/chemistry/comments/2t4p6k/has_anybody_ever_made_a_01_m_solution_of_sodium/
http://www.crscientific.com/experiment4.html
https://www.ou.edu/research/electron/bmz5364/buffers.html
http://delloyd.50megs.com/moreinfo/buffers2.html
https://www.pharmaguideline.com/2010/09/preparation-of-buffer-solutions.html
By definition buffer molarity is the additive of the molarities of the acid and its conjugate base. Therefore the molarity will not change when you mix two solutions of the same molarities. It would change only when water is added.
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