TEM is having a major problem with sample preparation, whereas XRD is relatively easy as far as sample preparation is concerned, I also found a paper in which XRD was a better method as that the TEM.
I can guess that using XRD you can measure the size the crystals from the amplitude of the diffraction peaks. Monocrystals have high peaks, polycrystalline materials have low diffraction peaks. If you know the size of the crystals you can approximate the dislocation density in that sample
dislocation density (dd) is calculated via XRD by dd =1/D2 *) with D being the crystallite size D, which is calculated via the ´Scherrer equation' or Williamson-Hall expression;
please see for example the answers to previous similar questions:
Hi Raghavendra Darji, I agreed with Valentin Bogatu and Gerhard Martens . The crystallite size of the sample can be determined from the broadening of the XRD peaks. Mathematically, the dislocation density (δ) can be calculated using:
δ =1/D2 where D is the crystallite size. The unit is nm–2.
Hi Raghavendra Darji, I agreed with Lee. Firtsly you have to calculate the crystallite size from the highly intensed park with proper broadness. Afterwards, you have to calculate the dislocations in nm^-2 by given expression Dr. Lee.
The Williamson-Smallman relation has to be regarded as a very rough estimate.
Already the starting point (Scherrer equation) with the shape factor will lead to a very rough estimate of D and further more the D has a distribution, which is not at all considered here. In addition residual stress is not considered too...