1 A m2 = 103 emu

When you took 5000 you cannot remove the units of density. Density is not unit less quantity..

Dear Bhushan ,

ive used the same relation. 

When you took 5000 you cannot remove the units of density. Density is not unit less quantity..

Magnetization(M) in emu/g multiplied by density of the sample gives you the 'M' in emu/cc, which is nothing but in Guass. Next as we know, 79.58 A m-1 = 1 G. Use this relation to get magnetization in A m-1

Multiply emu/g with density in g/cm3 and you get volume nagnetization in emu/cm3, multiply this by 1000 to get magnetization in A/m. (4*pi*M is in Gauss)

Dr. Gyergyek is right, and there are two way to calculate the value.

1. If you want convert emu/g to A/m, you can  multiply the value M in emu/g with the density in g/cm3, then the M is changed to the value in emu/cm3 or emu/cc. Because 1 emu/cc = 1000 A/m, so you can get the M in A/m by multiply 1000.

2. On the other hand, you can also calculate the value by 4*Pi*M, where M is in emu/cc, and the result  is in Gs.  Then you can get M in A/m by using 1 Gs= 79.6 A/m.

Thanks Jianbo Wang sir.

ive just multiplied by the density in Kg/m3 and getting the correct answers now

as 1000 Kg/m3 = 1 g/cm3 , 

can you please explain the 2nd way in detail.

Thanks again

the 2nd way is the same way with the first one.

because 4*Pi*79.6=4*Pi*1000/(4*Pi)=1000

just two methods to calculate, and different people like different ways.

2 nd way:

relatino in cgs system B=H+4*pi*M

So 4*pi*M is "induction" which is in G in cgs unit system while M is volume magnetization in emu/cm^3. Then you use the relation 4*pi*M in G = 10^3/4*pi(which is 79,6)=1A/m. So to change fields in G or Oe you multiply them by 79,6 and you get field in A/m, for magnetization you mulitply volume magnetization in g/cm^3 by 1000 to get it in A/m

Thanks alot

Jianbo Wang sir and Sašo Gyergyek  Sir .

Ive got the point.

For specific magnetization per unit mass (sigma) we normally use (emu/g) in CGS system, or (Am2/kg) in SI system. The conversion factor between these two quantities is 1; i.e., 1 emu/g = 1 Am2/kg. If you want the magnetization per unit volume (M = density * sigma), then multiplying the specific magnetization per unit mass by the density gives you the magnetization in emu/cm3. Now notice the following dimensional relation:

1 emu = 1 ab ampere * 1cm2

Therefore,

1 emu/cm3 = 1 ab ampere/cm

Now convert to the SI system knowing that 1 ab ampere = 10 amperes:

1 emu/cm3 =1 ab ampere/cm =10 A / 10-2 m = 1000 A/m = 1 kA/m

The unit A/m is the unit of the H-field in the SI system, which has a unit of Oe in CGS system of units. The conversion factor between these two quantities is 1000/(4pi) = 79.58 as mentioned above; i.e., 1 Oe = 79.58 A/m, and you find in the literature that the H-field (and coercivity HC for example) is expressed in either Oe or kA/m.

A yet third magnetic quantity (in addition to the specific magnetization sigma and the magnetization M) is the so called magnetic polarization J used in Kennelly convention and measured (normally) in Tesla. In CGS system, correlating the number of flux lines produced by M (which is 4Pi * M lines / cm2) and that produced by a field intensity H (1 Oe = 1 line/cm2), we conclude that:

1 emu/cm3 = 4Pi Oe  (Which is equal 103 A/m by the relation above). Therefore, we arrive at the relation:

1 Oe = (1000/4Pi) A/m = 79.58 A/m..........again

The conversion of the different magnetic units is not straight-forward, and requires knowledge of the definitions of these quantities. It is like a game in a sense!  

I agree with Saso.  This is a good conversion.

@Sami Mahmood

Thank you sir

I recommend the article entitled "Fundamental Physical Constants and Conversion Factors" by Bruce M. Moskowitz. Its a must read for all new researchers.

what is difference between emu/g and emu/gm?

Hello!

Units for Magnetic Properties

Reference: https://www.nist.gov/sites/default/files/documents/pml/electromagnetics/magnetics/magnetic_units.pdf

Please, see also discussion in the post https://www.researchgate.net/post/What_is_the_difference_between_magnetic_momentm_magnetizationM

Please see the attached file.

Pdf format

there are two way to calculate the value.

1. If you want convert emu/g to A/m, you can multiply the value M in emu/g with the density in g/cm3, then the M is changed to the value in emu/cm3 or emu/cc. Because 1 emu/cc = 1000 A/m, so you can get the M in A/m by multiply 1000.

2. On the other hand, you can also calculate the value by 4*Pi*M, where M is in emu/cc, and the result is in Gs. Then you can get M in A/m by using 1 Gs= 79.6 A/m.

1. Since 1 emu = 1 erg/G, convert emu/g to emu/cm3 by multiplying with density. Multiplying with 10^3 converts it to A/m which is also the SI unit.

Further conversion from A/m to Gauss can be done by multiplying by 4pi/10^3

To convert emu/g to A/m. Is a two step process. You multiply with the density of the material g/cm^3 to obtain volumetric magnetization emu/cc which 1 emu/cc=1000A/m or 1kA/m.

Most recent answer. To convert emu/g to A/m. Is a two step process. You multiply with the density of the material g/cm^3 to obtain volumetric magnetization emu/cc which 1 emu/cc=1000A/m or 1kA/m.

Dear Dr. Munjal et al.,

you can keep the CGS units for magnetization (emu/cm^3, G) and magnetic field (Oe) for any ¨pure¨ magnetic calculations/measurements. You need the SI units only if you want to account for electrical current (for instance, you consider the spin-torque effect). In this case, the SI current units (A, mA) are more convenient than the CGS ones.

https://www.ieeemagnetics.org/index.php?option=com_content&view=article&id=118&Itemid=107

If the mass and the volume of the sample are not being mentioned in the data file of VSM/PPMS, then how one may be able to convert "emu" into "emu/g" of "emu/cm^3"?

Can anyone guide me about the range of mass and the volume of the samples used in VSM/ PPMS?

Muhammad, the magnetization in ¨emu¨ units you cam convert to ¨emu/g" dividing by the sample weight. Then, if you now the nominal magnetic material density, multiply the number in ¨emu/g¨ by the density in ¨g/cm^3¨ and get the result in ¨emu/cm^3¨. 1 emu/cm^3 corresponds to approximately 80 (1000/4*pi) A/m.

Since VSM gives the resulting value of the magnetic moment for a certain amount of matter, and you need to know its value not for the body as a whole, but as the specific characteristics of the material, regardless of the mass or volume of the substance (in this case, magnetization), then you need to know the volume or mass of the body to determine the magnetization or the so-called specific magnetization, respectively. The conversion between them is performed using the density of the substance