You are using the world record microcrystalline cell process to make one cell in a module. The IV curve for this cell is ISC=30mA, VOC=.550v, and voltage and current at maximum power point (VMPP=.450v and IMPP=27.5mA). You can check that it has a fill factor of 75%.
Each cell in the module has an area of 100 cm2. The TCO you will use in the module adds a series resistance of 0.02 ohm.
If we assume that both the short circuit current and the IMPP do not change when the effect of the new TCO is taken into account, estimate the new fill factor (in %) of this solar cell.
Dear Mustafa Elbeltagy ,
The fill factor per definition
FF= Pmax/ Voc Isc
If a series resistance Rs is added, then the output power wil deecrease by the losses on Rs.
Since Rs remains constant at Impp, then the power lost in Rs = Impp^2 Rs
The new FF= (Pmax- Impp Rs^2)/Voc Isc. Then the change in the FF will be
FF= FFi ( 1 - Impp^2 Rs/ Pmax)
Impp= 27.5 mA , Rs= 0.02x 100/1.044=1.92 Ohm
Impp Rs^2= ( 27.5mA)^2 x 1.92= 1.452 mw, pmax=12.375 mw
FF= FFi (1- 1.452/12.375)=66.2 percent.
This is the estimated new FF because of the series resistance of TCO.
Best wishes
Dear Mustafa Elbeltagy
I agreed with Prof. Abdelhalim abdelnaby Zekry Basically, The Fill Factor (FF) is essentially a measure of quality of the solar cell, The FF is defined as the ratio of the maximum power from the solar cell to the product of Voc and Isc.
Kind Regards
Qamar Ul Islam
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