The topology shown in the figure is designated as seriesshunt? I am not able to figure that out. On the output side voltage sampling is being done.So it is shunt at the output. But I am seeing two feedback networks( marked in the figure)
Considering the red marked area ,the feedback topology is series shunt...but considering the yellow marked area , the feedback topology is shunt shunt.
What is the correct way of thinking?
I would call it a 'shunt-shunt' internal to a 'series-shunt',
and could be named a 'shared-shunt'.
I am suggesting a more flexible thinking paradigm,
and that there is never a single answer for every situation.
Md Tauseef,
The amplifier that you have given is "series-shunt" feedback. The portion that you have shown in red marked area will not act as feedback from output port to input port. Suppose the portion in yellow marked area is absent. Then whatever be the voltage across RL, the voltage input to MOSFET is Vs only, hence not "shunt-shunt " feedback.
Looks to me a Shunt-shunt feedback. Gate of MOS (Rin) would work like a virtual ground and Vs/Rs is input current.
A topology can also be decided by its impact on the impedance. A series connection increases impedance while shunt decreases it. In absence of feedback at input the impedance is infinity but with FB resistor connected the impedance is finite.
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