did any one have a UCF file for FPGA xillinx model zynq 7000
iam using ise to program this fpga my code is working will but in mapping process it is stop because it needs ucf file for zynq 7000
i have my own program using xillinix ISE to check this design i want to know how i made the UCF file for z board zynq 7000 the out put and input constrain
Xilinx ISE create UCF file .If you click top module in process menu you should select user constraint , in user constraint run I/O pin planning , in I/O pin planing you can assign signal's to the pins (It has pins name) and after that ISE make UCF file.
By clicking on the top module in Xillinx ISE you will find I/O pin planning in User Constrain, which you have to click on. These will open a new window (new simulator) called PlanAhead. In which there is a option of I/O ports where you can define the pin number. These will generate your .ucf file like attached here with.
Even you can directly modify the same file by just changing the port name and pin number.No need to open PlanAhead for further corrections.
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