How can you explain the color-anti color charge of gluons inside a baryon when all three quarks carry positve color charge? Where does the anti-color state for the binding gluon come from?
The new anti colour charge comes together with a new colour charge of the same colour.
For example, a red quark can emit a red+antiblue gluon, and the quark will then turn blue. The original red charge is still there (but moved to the gluon), and a blue and an antiblue charge are created in pair. The blue charged stays on the quark, while the antiblue is carried away by the gluon. So total colour charge is conserved.
So do you have then this superposition of colour states where a quark will carry all three colour charges in a baryon for instance? Without this idea of quarks in a baryon carrying all three colour charges I just dont quite get how there is just one red, one green and one blue quark making up the baryon with colour-aniticolour charged gluons playing the role you have explained above?
In addition to the explanation of C.Flensburg, the R+antiB gluon eventually absorbed by another B-quark and it turns to R. So initial state is R-quark + B-quark and the final state is B-quark + R-quark and the colour charge is conserved. Since the gluon is in virtual state, it need not be counted.
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